TAILIEUCHUNG - Math Word Problem Demystified Phần 6

Tham khảo tài liệu 'math word problem demystified phần 6', ngoại ngữ, anh ngữ phổ thông phục vụ nhu cầu học tập, nghiên cứu và làm việc hiệu quả | . LESSON 14 Solving Mixture Problems The equation is Alloy 1 Alloy 2 . Alloy 3 70 x 50 l2 - x 65 12 IMPLEMENTATION Solve the equation 70 x 50 12 - x 65 12 12 - x 12 6 - 6 - 6 - 6 o x _ X 9 ounces of Alloy 1 12 x 12 9 3 ounces of Alloy 2 Hence 9 ounces of the 70 alloy should be mixed with 3 ounces of the 50 alloy to get 12 ounces of an alloy which is 65 silver. EVALUATION Check the equation 70 x 50 12 - x 65 12 70 9 50 3 65 12 Another type of percent mixture requires that a mixture be diluted to make a weaker concentration of the mixture. If the amounts are the same then a portion of the higher concentration mixture must be removed and the same amount of the weaker mixture must be added. In this case the equation would look like this Mixture 1 Amount to be Amount of weaker mixture Mixture 2 removed to be added LESSON 14 Solving Mixture Problems The equation is Alloy 1 Alloy 2 Alloy 3 70 x 50 12 - X 65 12 IMPLEMENTATION Solve the equation 70 x 50 12 -x 65 12 12 - x 12 6 - 6 - 6 - 6 Ờ X _ o 02 X 9 ounces of Alloy 1 12 X 12-9 3 ounces of Alloy 2 Hence 9 ounces of the 70 alloy should be mixed with 3 ounces of the 50 alloy to get 12 ounces of an alloy which is 65 silver. EVALUATION Check the equation 70 x 50 12 - x 65 12 70 9 50 3 65 12 Another type of percent mixture requires that a mixture be diluted to make a weaker concentration of the mixture. If the amounts are the same then a portion of the higher concentration mixture must be removed and the same amount of the weaker mixture must be added. In this case the equation would look like this Mixture 1 Amount to be Amount of weaker mixture Mixture 2 removed to be added SON 14 Solving Mixture Problems The equation is Alloy 1 Alloy 2 Alloy 3 70 x 50 12 - x 65 12 IMPLEMENTATION Solve the equation 70 x 50 l2 - x 65 12 12 x 12 6 - 6-6 .

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