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Bộ tài liệu bài tập tham khảo môn vật lý bậc đại học bằng tiếng anh Chapter 23 | 23.1 AU kqxq2 -- 2.40 C -4.30 C i-------------------- 0.357J 1 0.354m 0.150m JT -At -0.357 J. 23.2 W -1.9xl0 8J -AU U -Uf Uf 1.9 10 SJ 5.4 10 SJ 1 J J 7.3xl0 8J 23.3 a E K U 1 00015 kg 22 0 m s 2.80xlQ- C 7 50xlC C 608 2 0.800 m r 1 2 kqAq2 2 0.608 J - 0.491 J c . Et Ef mvf - -E- v p---------------1 12.5 m s. f 2 f rf f 0.0015 kg 1 b At the closest point the velocity is zero 0.608 1 1 . . 2 80 x 10- C 7 80 x 10 6C _ Q m r 0.608 J 23.4 C -0400J r -t 230xl0-6C 720xl0 C 0373m r -0.400 J 23.5 a t OxlO C 1.20x1 O C _ Q r 0.250 m b i Kf K U -Uf 0 J 1 4.60 x 10 C 1.20 x 10 C -- 0 0994 J 0.25m 0.5 mJ Kf 0.0994 J -mv i v I 2 0 0994 J 26.6 m s 7 2 f f p.SOxlO kg ii Kf 0.189 J vf 36.7m s. iii Kf 0.198 J vf 37 6m s. 23.6 kq2 2kq2 0.500m 0.500 m 6kq2 6 1.2x10 C 2 0.078 J. 23.7 a 4.00 nC 3.00 nC 4.00 nC 2.00 nC U k qq qq qq k r r r V r12 r13 r23 J 0.200 m V 0.100m 3.00 nC 2.00 nC 0.100 m J 3.60 x 10 7 J. b IfU 0 0 kI qq I. So solving for x we find V ri2 X ri2 XJ 0 60 8------6 60x2 26x 1.6 0 x 0.074 m 0.360 m. Therefore x 0.2 x x 0.074 m since it is the only value between the two charges. 23.8 From Example 23.1 the initial energy Et can be calculated Et Ki Ut 2 9.11 x 10 31kg 3.00 x 106 m s 2 k 1.60 x 10 19C 3.20 x 10 19C 10 10 m Et 5.09 x 10 19 J. When velocity equals zero all energy is electric potential energy so 5.09 x 10 19 J 22 - r 9.06 x 10 10 m. r 23.9 Since the work done is zero the sum of the work to bring in the two equal charges q must equal the work done in bringing in charge Q. w w q q Wqq WqQ d d Q 2. 23.10 The work is the potential energy of the combination. U 1 Upe U _ ke 2e ke - e k - e 2e S 2 x 10-10m 5 x 10-10m 5 x 10-10m _--- i -1-21 5 x 10-10m 2 _ 9.0 x 109 Nm2 C2 1.6 x 10-19 C 2 2 __ 31 5 x 10- 10m J1 _ -7.31 x 10-19 J Since U is negative we want do 7.31 x 10 19 J to separate the particles 23.11 K1 U1 K2 U2 K1 U2 0 so K2 U1 U1 -e f- - - 1 5e with r 8.00 x 10 1 m 4n r r r 4n r U1 1.44 x 10 18 J 9.00 eV 23.12 Get closest distance y. Energy conservation mv2 .
