TAILIEUCHUNG - Báo cáo toán học: "Descents in Noncrossing Trees."

Tuyển tập các báo cáo nghiên cứu khoa học ngành toán học tạp chí toán học quốc tế đề tài: Descents in Noncrossing Trees. | Descents in Noncrossing Trees. David S. Hough Department of Mathematics Howard University Washington DC USA Submitted Jun 18 2002 Accepted Oct 6 2003 Published Oct 13 2003 MR Subject Classifications 05C30 05A15 Abstract The generating function for descents in noncrossing trees is found. A bijection shows combinatorially why the descent generating function with descents set equal to 2 is the generating function for connected noncrossing graphs. 1 Introduction A noncrossing tree is a tree drawn on n points numbered in counterclockwise order on a circle such that the edges lie entirely within the circle and do not cross. A descent is an edge from a higher to a lower label along a path from the root 1. We frequently use . to stand for generating function . In Section 2 we find the descent . for noncrossing trees. In Section 3 we show a bijection between noncrossing trees and connected noncrossing graphs that explains combinatorially why the . for connected noncrossing graphs equals the descent . evaluated at 2. 2 Descents in Noncrossing Trees Consider as in 2 a noncrossing tree as a sequence of butterflies. Let T z u v X z ud T 1 T where the sum is over all trees T the size tI is the number of edges d r is the number of descents and a T is the number of ascents. A butterfly is an ordered pair of subtrees T and T that lie on either side of an edge 1 i from the root to point i T on points Thanks to Louis W. Shapiro and Frank W. Schmidt for useful discussions and to the anonymous referee for an alternative proof that also proved a conjecture in the original paper. THE ELECTRONIC JOURNAL OF COMBINATORICS 10 2003 N13 1 greater than or equal to i and T on points less than or equal to i not including 1. Then we have T z u v 1 - vzT z u v T z v u 2 Figure 1 A butterfly diagram of noncrossing trees where T stands for T z u v and T for T z v u . This is because when the tree is rooted at 1 every edge from 1 contributes one to the size and one

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