TAILIEUCHUNG - SAT II Physics (SN) Episode 2 Part 2

Tham khảo tài liệu 'sat ii physics (sn) episode 2 part 2', ngoại ngữ, ngữ pháp tiếng anh phục vụ nhu cầu học tập, nghiên cứu và làm việc hiệu quả | simply the product of the current and the resistance. The voltage drop across the two resistors is Note that the voltage drop across the two resistors is 10 V 20 V 30 V which is the total voltage drop across the circuit. Resistors in Parallel Two resistors are in parallel when the circuit splits in two and one resistor is placed on each of the two branches. In this circumstance it is often useful to calculate the equivalent resistance as if there were only one resistor rather than deal with each resistor individually. Calculating the equivalent resistance of two or more resistors in parallel is a little more complicated than calculating the total resistance of two or more resistors in series. Given two resistors and in parallel the equivalent resistance is When a circuit splits in two the current is divided between the two branches though the current through each resistor will not necessarily be the same. The voltage drop must be the same across both resistors so the current will be stronger for a weaker resistor and vice versa. EXAMPLE Two resistors 5 and 20 are set up in parallel as in the diagram above. The battery produces a potential difference of 12 V. What is the total resistance in the circuit What is the current running through and What is the power dissipated in the resistors WHAT IS THE TOTAL RESISTANCE IN THE CIRCUIT Answering this question is just a matter of plugging numbers into the formula for resistors in parallel. 226 So 4 . WHAT IS THE CURRENT RUNNING THROUGH R1 AND R2 We know that the total voltage drop is 12 V and since the voltage drop is the same across all the branches of a set of resistors in parallel we know that the voltage drop across both resistors will be 12 V. That means we just need to apply Ohm s Law twice once to each resistor If we apply Ohm s Law to the total resistance in the system we find that 12 V 4 3 A. As we might expect the total current through the system is the sum of the current through each of the two branches. The .

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