TAILIEUCHUNG - Tribology in Machine Design 2009 Part 5

Tham khảo tài liệu 'tribology in machine design 2009 part 5', kỹ thuật - công nghệ, cơ khí - chế tạo máy phục vụ nhu cầu học tập, nghiên cứu và làm việc hiệu quả | 108 Tribology in machine design Efficiency tv n - tana 1 p tana tan a 1 tan 2 Writing tan 2 frm r the efficiency becomes tana r ------ - tan a 0i rm r where tan Ị is the true coefficient of friction for all contact surfaces. This result is of a similar form to eqn and can be deduced directly in the same manner. In the case of the rotating nut c fWrm is the friction couple for the bearing surface of the nut and if the pressure is assumed uniformly distributed . rỊ-rĩ. 2 n 2 m 3 .2 .2 where rỵ and r2 are the external and internal radii respectively of the contact surface. Comparing eqn with eqn it will be noticed that in the former p is the horizontal component of the reaction at the contact surfaces of the nut and screw whereas in the latter p is the horizontal effort on the nut at radius r . in the latter case Pr f Wrm Wr tan a Ộ1 or p w tan a i which is another form of eqn . Numerical example Find the efficiency and the mechanical advantage of a screw jack when raising a load using the following data. The screw has a single-start square thread the outer diameter of which is five times the pitch of the thread and is rotated by a lever the length of which measured to the axis of the screw is ten times the outer diameter of the screw the coefficient of friction is . The load is free to rotate. Solution Assuming that the screw rotates in a fixed nut then since the load is free to rotate friction at the swivel head does not arise so that c 0. Further it Friction lubrication and wear in lower kinematic pairs 109 must be remembered that the use of a single lever will give rise to side friction due to the tilting action of the screw unless the load is supported laterally. For a single-start square thread of pitch p and diameter d depth of thread p so mean radius rjd ip but d 5p 1 9 r ỉ d d -d 2 20 20 . p 14 tan 7 J- Inr 2n 9 7 4 3 f tan Ộ 0 6 51 a 0 io 54 now . . . QL p Kztan 7 0 - r . . load w L mechanical advantage -

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